What is the critical x^4e^{-x/2} ?

The critical x^4e^{-x/2} is x=0,x=8

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critical x^4e^{-x/2}

critical points

x^{4} e^{- \frac{x}{2}}

x = 0, x = 8

Solution steps

x^{4} e^{- \frac{x}{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 8

Identify critical points not in

f (x)

domain

Domain of

x^{4} e^{- \frac{x}{2}} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 8

9 x + 6 y = 36

4 x - 2 y = 14

\frac{6 x + 5}{1 - 3 x}

f (x) = \frac{x}{1 - ln ( x - 2 )}

f (x) = \frac{x ^{2}}{x + 1}