What is the extreme f(x)=x^3-9x^2+15x+1 ?

The extreme f(x)=x^3-9x^2+15x+1 is Maximum(1,8),Minimum(5,-24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-9x^2+15x+1

extreme points

f (x) = x^{3} - 9 x^{2} + 15 x + 1

Maximum (1, 8), Minimum (5, - 24)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x + 15

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 1

into

x^{3} - 9 x^{2} + 15 x + 1 : 8

Maximum (1, 8)

Plug

x = 5

into

x^{3} - 9 x^{2} + 15 x + 1 : - 24

Minimum (5, - 24)

Maximum (1, 8), Minimum (5, - 24)

(6, 2), (4, 4)

f (x) = 100 - 4 y

f (x) = (x - 6)^{\frac{1}{2}}

f (x) = \frac{5 x + 9}{4 x}

f (x) = ∣ x - 2 ∣

What is the extreme f(x)=x^3-9x^2+15x+1 ?
The extreme f(x)=x^3-9x^2+15x+1 is Maximum(1,8),Minimum(5,-24)