What is the inverse of (x-2)/(sqrt(x+1)) ?

The inverse of (x-2)/(sqrt(x+1)) is (4+x^2+xsqrt(x^2+12))/2 ,(4+x^2-xsqrt(x^2+12))/2

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inverse of (x-2)/(sqrt(x+1))

inverse

\frac{x - 2}{x + 1}

\frac{4 + x ^{2} + x x ^{2} + 12}{2}, \frac{4 + x ^{2} - x x ^{2} + 12}{2}

Solution steps

y = \frac{x - 2}{x + 1}

Replace

x

with

y

x = \frac{y - 2}{y + 1}

Solve for

y, x = \frac{y - 2}{y + 1}

\frac{4 + x ^{2} + x x ^{2} + 12}{2}, \frac{4 + x ^{2} - x x ^{2} + 12}{2}

f (x) = 6^{x} - 7

f (x) = 2^{5 - 8 x}

sin (x) + 8

6 x - 2 x = 3

\frac{x ^{2} - 6 x + 12}{x - 4}

What is the inverse of (x-2)/(sqrt(x+1)) ?
The inverse of (x-2)/(sqrt(x+1)) is (4+x^2+xsqrt(x^2+12))/2 ,(4+x^2-xsqrt(x^2+12))/2