What is the inverse of f(x)= 1/4 x^3-6 ?

The inverse of f(x)= 1/4 x^3-6 is cube root of 4x+24

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inverse of f(x)= 1/4 x^3-6

inverse

f (x) = \frac{1}{4} x^{3} - 6

3 4 x + 24

Solution steps

y = \frac{1}{4} x^{3} - 6

Replace

x

with

y

x = \frac{1}{4} y^{3} - 6

Solve for

y, x = \frac{1}{4} y^{3} - 6

3 4 x + 24

f (x) = 11 x - 9

f (x) = \frac{x ^{2} + 3}{5 - x}

e^{x} - 2

f (x) = x^{4} - 4 x^{2}

f (x) = 2 x^{3} - 3 x^{2} - 8 x + 1

What is the inverse of f(x)= 1/4 x^3-6 ?
The inverse of f(x)= 1/4 x^3-6 is cube root of 4x+24