What is the domain of f(x)=sqrt(4+3x) ?

The domain of f(x)=sqrt(4+3x) is x>=-4/3

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domain of f(x)=sqrt(4+3x)

domain

f (x) = 4 + 3 x

x \geq - \frac{4}{3}

Interval Notation

[- \frac{4}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{4}{3}

The function domain

x \geq - \frac{4}{3}

f (x) = 13 x^{3} - 1

f (x) = (x + 2)^{\frac{1}{3}} + 2

f (x) = \frac{1}{4 x}

∣ x ∣ - 5

5 x - 3 y = - 15

What is the domain of f(x)=sqrt(4+3x) ?
The domain of f(x)=sqrt(4+3x) is x>=-4/3