What is the domain of f(x)=sqrt(3-(x-3)^2)-2 ?

The domain of f(x)=sqrt(3-(x-3)^2)-2 is -sqrt(3)+3<= x<= sqrt(3)+3

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domain of f(x)=sqrt(3-(x-3)^2)-2

domain

f (x) = 3 - (x - 3)^{2} - 2

- 3 + 3 \leq x \leq 3 + 3

Interval Notation

[- 3 + 3, 3 + 3]

Solution steps

Find non-negative values for radicals:

- 3 + 3 \leq x \leq 3 + 3

The function domain

- 3 + 3 \leq x \leq 3 + 3

f (x) = \frac{4}{x - 2}

\frac{1}{x ^{2} - 9 x + 14}

f (1) = \frac{x ^{2} + 4 x + 4}{x ^{2} + 2 x - 3}

\frac{- 1}{2 9 - x}

What is the domain of f(x)=sqrt(3-(x-3)^2)-2 ?
The domain of f(x)=sqrt(3-(x-3)^2)-2 is -sqrt(3)+3<= x<= sqrt(3)+3