What is the inverse of f(x)=sin((1-9x)/x) ?

The inverse of f(x)=sin((1-9x)/x) is 1/(9+arcsin(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sin((1-9x)/x)

inverse

f (x) = sin (\frac{1 - 9 x}{x})

\frac{1}{9 + arcsin ( x )}

Solution steps

sin (a) = b \Rightarrow a = arcsin (b)

\frac{1 - 9 x}{x} = arcsin (y)

Solve for

x, \frac{1 - 9 x}{x} = arcsin (y)

\frac{1}{9 + arcsin ( y )}

Substitute

y = x

\frac{1}{9 + arcsin ( x )}

f (x) = 5 x^{2} - 7 x - 6

f (x) = - 6 x + 5 y = 9

f (x) = x^{3} + 2

f (x) = \frac{- 3 x - 9}{5 x + 15}

f (x) = 2 x^{2} - 6 x + 11

What is the inverse of f(x)=sin((1-9x)/x) ?
The inverse of f(x)=sin((1-9x)/x) is 1/(9+arcsin(x))