What is the domain of f(x)=((x^2+4))/(x^2-9) ?

The domain of f(x)=((x^2+4))/(x^2-9) is x 3

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domain of f(x)=((x^2+4))/(x^2-9)

domain

f (x) = \frac{( x ^{2} + 4 )}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

sec (x) csc (x)

f (x) = 3 x - x^{3}

f (x) = lo g_{6} (x + 7)

f (x) = x^{3} + 2 x^{2}

\frac{1}{x + 2}

What is the domain of f(x)=((x^2+4))/(x^2-9) ?
The domain of f(x)=((x^2+4))/(x^2-9) is x<-3\lor-3<x<3\lor x>3