What is the domain of f(x)= 1/(sqrt(x^2-5x+4)) ?

The domain of f(x)= 1/(sqrt(x^2-5x+4)) is x 4

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domain of f(x)= 1/(sqrt(x^2-5x+4))

domain

f (x) = \frac{1}{x ^{2} - 5 x + 4}

x < 1 or x > 4

Interval Notation

(- \infty, 1) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 1

Combine real regions and undefined points for final function domain

x < 1 or x > 4

f (x) = \frac{6 e ^{x}}{e ^{x} - 9}

f (x) = x^{2} - 4

f (x) = (3) lo g_{5} (7 x - 4)

x^{2} - 5 x + 6

f (x) = \frac{x + 4}{6} + \frac{y + 3}{3} = 2

What is the domain of f(x)= 1/(sqrt(x^2-5x+4)) ?
The domain of f(x)= 1/(sqrt(x^2-5x+4)) is x<1\lor x>4