What is the critical (ln(x))/(x^2) ?

The critical (ln(x))/(x^2) is x=sqrt(e)

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critical (ln(x))/(x^2)

critical points

\frac{ln ( x )}{x ^{2}}

x = e

Solution steps

\frac{ln ( x )}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = e, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{ln ( x )}{x ^{2}} : x > 0

\frac{ln ( x )}{x ^{2}}

is not defined at

x = 0

, therefore:

x = e

f (x) = cos (2 x + π)

9 - x^{2}

\frac{3}{x - 1}

f (x) = \frac{x - 1}{x + 3}

(1, - 9), (- 5, 0)