What is the range of f(x)=sqrt(x+7)-9 ?

The range of f(x)=sqrt(x+7)-9 is f(x)>=-9

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range of f(x)=sqrt(x+7)-9

range

f (x) = x + 7 - 9

f (x) \geq - 9

Interval Notation

[- 9, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = - 9

f (x) \geq - 9

(2.3) (10.3)

\frac{- 4}{- ( \frac{- 8}{- 2 x - 6} ) + 4}

f (x) = 2 + x - 5

f (x) = 0.5 x^{2}

3 x - 9 y = 8

What is the range of f(x)=sqrt(x+7)-9 ?
The range of f(x)=sqrt(x+7)-9 is f(x)>=-9