What is the domain of f(x)=(2x^3-250)/(x^2-2x-15) ?

The domain of f(x)=(2x^3-250)/(x^2-2x-15) is x 5

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domain of f(x)=(2x^3-250)/(x^2-2x-15)

domain

f (x) = \frac{2 x ^{3} - 250}{x ^{2} - 2 x - 15}

x < - 3 or - 3 < x < 5 or x > 5

Interval Notation

(- \infty, - 3) \cup (- 3, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 3

The function domain

x < - 3 or - 3 < x < 5 or x > 5

f (x) = x^{2} + 2 x - 3

f (x) = 16 x^{2} + 1

f (x) = \frac{x}{x ^{2} - 1}

- 2 x^{2} - 2 x - 2

f (x) = \frac{2}{x + 3}

What is the domain of f(x)=(2x^3-250)/(x^2-2x-15) ?
The domain of f(x)=(2x^3-250)/(x^2-2x-15) is x<-3\lor-3<x<5\lor x>5