What is the domain of (5^{1/x})/((x+1)^2) ?

The domain of (5^{1/x})/((x+1)^2) is x 0

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domain of (5^{1/x})/((x+1)^2)

domain

\frac{5 ^{\frac{1}{x}}}{( x + 1 ) ^{2}}

x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 0

The function domain

x < - 1 or - 1 < x < 0 or x > 0

f (x) = - x + 13

\frac{2 x + 7}{5 x + 4}

- x - 2 - 3

y = 3 x^{2} - x^{3}

(1.8) (9.2)

What is the domain of (5^{1/x})/((x+1)^2) ?
The domain of (5^{1/x})/((x+1)^2) is x<-1\lor-1<x<0\lor x>0