What is the domain of f(x)=((2x^2)/(2x+4)) ?

The domain of f(x)=((2x^2)/(2x+4)) is x -2

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domain of f(x)=((2x^2)/(2x+4))

domain

f (x) = (\frac{2 x ^{2}}{2 x + 4})

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

y = x - 5

f (x) = - \frac{13}{( 4 + x ) ^{2}}

\frac{x + 15}{x - 5}

1 - x - x^{2}

f (x) = x - 2

What is the domain of f(x)=((2x^2)/(2x+4)) ?
The domain of f(x)=((2x^2)/(2x+4)) is x<-2\lor x>-2