What is the critical f(x)=6x^{2/3}+x^{5/3} ?

The critical f(x)=6x^{2/3}+x^{5/3} is x=-12/5 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=6x^{2/3}+x^{5/3}

critical points

f (x) = 6 x^{\frac{2}{3}} + x^{\frac{5}{3}}

x = - \frac{12}{5}, x = 0

Solution steps

6 x^{\frac{2}{3}} + x^{\frac{5}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{12}{5}, x = 0

Identify critical points not in

f (x)

domain

Domain of

6 x^{\frac{2}{3}} + x^{\frac{5}{3}} : - \infty < x < \infty

All critical points are in domain

x = - \frac{12}{5}, x = 0

f (x) = 3 x - 4

f (x) = \frac{4}{x - 1} - 2

\frac{1}{x ^{2} - x}

f (x) = \frac{2 x + 1}{7}

f (x) = x e^{2 x}

What is the critical f(x)=6x^{2/3}+x^{5/3} ?
The critical f(x)=6x^{2/3}+x^{5/3} is x=-12/5 ,x=0