What is the inflection f(x)=4x^3-6x^2+7x-8 ?

The inflection f(x)=4x^3-6x^2+7x-8 is (1/2 ,-11/2)

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inflection f(x)=4x^3-6x^2+7x-8

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 7 x - 8

(\frac{1}{2}, - \frac{11}{2})

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 7 x - 8 : - \frac{11}{2}

(\frac{1}{2}, - \frac{11}{2})

f (x) = - 8 x + 16

f (x) = x^{2} - x + 2

f (x) = \frac{3 x - 4}{2 x + 11}

f (x) = \frac{x ^{2} - 4 x + 3}{x - 1}

f (x) = - 13

What is the inflection f(x)=4x^3-6x^2+7x-8 ?
The inflection f(x)=4x^3-6x^2+7x-8 is (1/2 ,-11/2)