What is the inverse of f(x)=5+(10+x)^{1/2} ?

The inverse of f(x)=5+(10+x)^{1/2} is x^2-10x+15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=5+(10+x)^{1/2}

inverse

f (x) = 5 + (10 + x)^{\frac{1}{2}}

x^{2} - 10 x + 15

Solution steps

y = 5 + (10 + x)^{\frac{1}{2}}

Replace

x

with

y

x = 5 + (10 + y)^{\frac{1}{2}}

Solve for

y, x = 5 + (10 + y)^{\frac{1}{2}}

x^{2} - 10 x + 15

f (x) = - 0.0017 x + 0.2625

f (x) = \frac{- 2}{x}

f (x) = - 0.3 x + 229

y = 1 - x^{2}

x^{2} - y^{2} = 1

What is the inverse of f(x)=5+(10+x)^{1/2} ?
The inverse of f(x)=5+(10+x)^{1/2} is x^2-10x+15