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Popular >

range of x^2+8

Solution

range

x^{2} + 8

Solution

f (x) \geq 8

+1

Interval Notation

[8, \infty)

Solution steps

Vertex of

x^{2} + 8 :

Minimum

(0, 8)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (0, 8)

f (x) \geq 8

Popular Examples

domain of f(x)= 3/(x^2+2x)domain

f (x) = \frac{3}{x ^{2} + 2 x}

inverse of f(x)=3x+7 inverse

f (x) = 3 x + 7

domain of sqrt((7x+1)/(4x-3)-2)domain

\frac{7 x + 1}{4 x - 3} - 2

slope ofintercept y-9= 7/2 (x-2)slope intercept

y - 9 = \frac{7}{2} (x - 2)

f (x) = tanh (x)

Frequently Asked Questions (FAQ)

What is the range of x^2+8 ?
The range of x^2+8 is f(x)>= 8