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Popular >

extreme f(x)=-1/(x^2+5)

Solution

extreme points

f (x) = - \frac{1}{x ^{2} + 5}

Solution

Minimum (0, - \frac{1}{5})

Solution steps

f^{'} (x) = \frac{2 x}{( x ^{2} + 5 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

- \frac{1}{x ^{2} + 5} : - \frac{1}{5}

Minimum (0, - \frac{1}{5})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-1/(x^2+5) ?
The extreme f(x)=-1/(x^2+5) is Minimum(0,-1/5)