en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (6,3),(10,-7)

Solution

midpoint

(6, 3), (10, - 7)

Solution

(8, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (6, 3), (x_{2}, y_{2}) = (10, - 7)

= (\frac{10 + 6}{2}, \frac{- 7 + 3}{2})

Refine

= (8, - 2)

Popular Examples

inverse of f(x)=(3x+5)/(7x+4)inverse

f (x) = \frac{3 x + 5}{7 x + 4}

domain of f(x)=sqrt(x)+sqrt(4-x)domain

f (x) = x + 4 - x

domain of sqrt(12-x)domain

12 - x

domain of (36x^2+81x)/((9x-4)^2)domain

\frac{36 x ^{2} + 81 x}{( 9 x - 4 ) ^{2}}

domain of f(x)= 3/(y+1)-4 domain

f (x) = \frac{3}{y + 1} - 4

Frequently Asked Questions (FAQ)

What is the midpoint (6,3),(10,-7) ?
The midpoint (6,3),(10,-7) is (8,-2)