What is the domain of 1+cot(x-pi/4) ?

The domain of 1+cot(x-pi/4) is pin<= x< pi/4+pin\lor pi/4+pin<x<pi+pin

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domain of 1+cot(x-pi/4)

domain

1 + cot (x - \frac{π}{4})

πn \leq x < \frac{π}{4} + πn or \frac{π}{4} + πn < x < π + πn

Interval Notation

[πn, \frac{π}{4} + πn) \cup (\frac{π}{4} + πn, π + πn)

Solution steps

Take the denominator(s) of

1 + cot (x - \frac{π}{4})

and compare to zero:

x = \frac{π}{4} + πn

Periodicity of

1 + cot (x - \frac{π}{4}) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{4} + πn or \frac{π}{4} + πn < x < π + πn

y = 3 x^{2} + 6 x + 2

y = - 5 x - 7

- 14 x + 4 y = - 10

f (x) = \frac{3 + 2 x}{x - 1}

f (x) = x^{4} - x^{2} + 4

What is the domain of 1+cot(x-pi/4) ?
The domain of 1+cot(x-pi/4) is pin<= x< pi/4+pin\lor pi/4+pin<x<pi+pin