What is the critical f(x)=(x+4)^2(x-2) ?

The critical f(x)=(x+4)^2(x-2) is x=-4,x=0

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critical f(x)=(x+4)^2(x-2)

critical points

f (x) = (x + 4)^{2} (x - 2)

x = - 4, x = 0

Solution steps

(x + 4)^{2} (x - 2)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 0

Identify critical points not in

f (x)

domain

Domain of

(x + 4)^{2} (x - 2) : - \infty < x < \infty

All critical points are in domain

x = - 4, x = 0

x^{2} - x - 6

f (x) = \frac{7 x}{9 x - 1}

y = (x + 5) (x + 3)

\frac{8}{7 + x}

f (x) = \frac{3 x - 1}{- 1 + 9 x ^{2}}

What is the critical f(x)=(x+4)^2(x-2) ?
The critical f(x)=(x+4)^2(x-2) is x=-4,x=0