What is the critical f(x)=6sqrt(x)-6x ?

The critical f(x)=6sqrt(x)-6x is x=0,x= 1/4

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critical f(x)=6sqrt(x)-6x

critical points

f (x) = 6 x - 6 x

x = 0, x = \frac{1}{4}

Solution steps

6 x - 6 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{4}, x = 0

Identify critical points not in

f (x)

domain

Domain of

6 x - 6 x : x \geq 0

All critical points are in domain

x = 0, x = \frac{1}{4}

y = \frac{1}{2} (x - 3)^{2} + 5

f (x) = - x^{2} + 3 x + 4

12 p

y = - x + 1

What is the critical f(x)=6sqrt(x)-6x ?
The critical f(x)=6sqrt(x)-6x is x=0,x= 1/4