What is the range of f(x)= x/(x^2+x-6) ?

The range of f(x)= x/(x^2+x-6) is -infinity <f(x)<infinity

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range of f(x)= x/(x^2+x-6)

range

f (x) = \frac{x}{x ^{2} + x - 6}

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Rewrite as

\frac{x}{x ^{2} + x - 6} = y

Multiply both sides by

x^{2} + x - 6

x = y (x^{2} + x - 6)

The range is the set of y for which the discriminant is greater or equal to zero

Discriminant

x = y (x^{2} + x - 6) : 25 y^{2} - 2 y + 1

25 y^{2} - 2 y + 1 \geq 0 :

True for all

y \in R

Therefore the range is

- \infty < f (x) < \infty

\frac{4}{x ^{2} - 3 x}

f (x) = 4^{x - 5} + 2

f (x) = \frac{7 + x}{1 - x}

f (x) = \frac{x - 5}{3 x ^{2}}

f (x) = x^{3} - 27 x + 3

What is the range of f(x)= x/(x^2+x-6) ?
The range of f(x)= x/(x^2+x-6) is -infinity <f(x)<infinity