What is the inverse of f(x)=19+\sqrt[3]{x} ?

The inverse of f(x)=19+\sqrt[3]{x} is x^3-57x^2+1083x-6859

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inverse of f(x)=19+\sqrt[3]{x}

inverse

x^{3} - 57 x^{2} + 1083 x - 6859

Solution steps

Replace

x

with

y

Solve for

x^{3} - 57 x^{2} + 1083 x - 6859

\frac{- 4 x - 20}{x ^{2} - 25}

g (x) = x - 2

2 x + 2 y = 16

(1, 7), (- 4, 6)

y - 2 = \frac{9}{2} (x + 8)

What is the inverse of f(x)=19+\sqrt[3]{x} ?
The inverse of f(x)=19+\sqrt[3]{x} is x^3-57x^2+1083x-6859