What is the monotone f(x)=sqrt(x^2-9) ?

The monotone f(x)=sqrt(x^2-9) is Decreasing:-infinity <x<-3,Increasing:3<x<infinity

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monotone f(x)=sqrt(x^2-9)

monotone intervals

f (x) = x^{2} - 9

Decreasing : - \infty < x < - 3, Increasing : 3 < x < \infty

Solution steps

f^{'} (x) = \frac{x}{x ^{2} - 9}

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: 3 < x < \infty

Decreasing : - \infty < x < - 3, Increasing : 3 < x < \infty

f (x) = (x + 7)^{\frac{1}{2}}

f (x) = e^{x}

y = 3 x - 2, (2, 11)

lo g_{2} (2 x)

17 x + y = - 9

What is the monotone f(x)=sqrt(x^2-9) ?
The monotone f(x)=sqrt(x^2-9) is Decreasing:-infinity <x<-3,Increasing:3<x<infinity