What is the extreme f(x)=x^3-3x^2-9x ?

The extreme f(x)=x^3-3x^2-9x is Maximum(-1,5),Minimum(3,-27)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x^2-9x

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x

Maximum (- 1, 5), Minimum (3, - 27)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x : 5

Maximum (- 1, 5)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x : - 27

Minimum (3, - 27)

Maximum (- 1, 5), Minimum (3, - 27)

f (x) = \frac{( 3 x + x ^{3} + 2 )}{4 x ^{3} - 3 x ^{2} - 5}

f (x) = x^{2} - 4, x \geq 0

2 x^{3} - 4 x^{2}

f (x) = 20 - 5 x

f (x) = - 5 x

What is the extreme f(x)=x^3-3x^2-9x ?
The extreme f(x)=x^3-3x^2-9x is Maximum(-1,5),Minimum(3,-27)