What is the domain of f(x)=sqrt(8x-3) ?

The domain of f(x)=sqrt(8x-3) is x>= 3/8

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domain of f(x)=sqrt(8x-3)

domain

f (x) = 8 x - 3

x \geq \frac{3}{8}

Interval Notation

[\frac{3}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{3}{8}

The function domain

x \geq \frac{3}{8}

f (x) = x 256 - x^{2}

\frac{x}{x + 4}

(- 3, - 3), (2, 9)

f (x) = x^{2} + 2 y^{2} x^{2} + y^{2} = 1

f (x) = \frac{4 x + 2}{3 x - 6}

What is the domain of f(x)=sqrt(8x-3) ?
The domain of f(x)=sqrt(8x-3) is x>= 3/8