What is the inverse of f(x)=3-2x-x^2 ?

The inverse of f(x)=3-2x-x^2 is -1-sqrt(-x+4),-1+sqrt(-x+4)

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inverse of f(x)=3-2x-x^2

inverse

f (x) = 3 - 2 x - x^{2}

- 1 - - x + 4, - 1 + - x + 4

Solution steps

y = 3 - 2 x - x^{2}

Replace

x

with

y

x = 3 - 2 y - y^{2}

Solve for

y, x = 3 - 2 y - y^{2}

- 1 - - x + 4, - 1 + - x + 4

f (x) = \frac{x + 2}{x ^{2} - 4}

f (x) = \frac{16 - x ^{2}}{x + 3}

2 x - 3 y = 8

f (x) = 6 tan (0.2 x)

f (x) = \frac{3}{x + 4}

What is the inverse of f(x)=3-2x-x^2 ?
The inverse of f(x)=3-2x-x^2 is -1-sqrt(-x+4),-1+sqrt(-x+4)