What is the domain of f(x)=((2x+3))/(x(x^2+2x-3)) ?

The domain of f(x)=((2x+3))/(x(x^2+2x-3)) is x 1

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domain of f(x)=((2x+3))/(x(x^2+2x-3))

domain

f (x) = \frac{( 2 x + 3 )}{x ( x ^{2} + 2 x - 3 )}

x < - 3 or - 3 < x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 0 or 0 < x < 1 or x > 1

f (x) = 23 (x - 11)

y = x^{2} - 2 x - 3

f (x) = \frac{8 - x}{5}

f (x) = - x^{3} + x^{2} + 4 x - 2

y = 6 x

What is the domain of f(x)=((2x+3))/(x(x^2+2x-3)) ?
The domain of f(x)=((2x+3))/(x(x^2+2x-3)) is x<-3\lor-3<x<0\lor 0<x<1\lor x>1