What is the inverse of f(x)=(x-15)^2,x<= 15 ?

The inverse of f(x)=(x-15)^2,x<= 15 is sqrt(x)+15,-sqrt(x)+15

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inverse of f(x)=(x-15)^2,x<= 15

inverse

f (x) = (x - 15)^{2}, x \leq 15

x + 15, - x + 15

Solution steps

y = (x - 15)^{2}

Replace

x

with

y

x = (y - 15)^{2}

Solve for

y, x = (y - 15)^{2}

x + 15, - x + 15

f (x) = 20 x^{3}

x^{2} - 2 x + 5

f (x) = \frac{3 x - 5}{x + 1}

x - \frac{1}{x}

f (x) = \frac{x - 2}{x ^{2} + 5 x + 4}

What is the inverse of f(x)=(x-15)^2,x<= 15 ?
The inverse of f(x)=(x-15)^2,x<= 15 is sqrt(x)+15,-sqrt(x)+15