What is the inverse of f(x)=((x+7))/(x-3) ?

The inverse of f(x)=((x+7))/(x-3) is (7+3x)/(x-1)

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inverse of f(x)=((x+7))/(x-3)

inverse

f (x) = \frac{( x + 7 )}{x - 3}

\frac{7 + 3 x}{x - 1}

Solution steps

y = \frac{x + 7}{x - 3}

Replace

x

with

y

x = \frac{y + 7}{y - 3}

Solve for

y, x = \frac{y + 7}{y - 3}

\frac{7 + 3 x}{x - 1}

\frac{x - 3}{7}

f (x) = \frac{x + 14}{x - 11}

\frac{7}{7 + 3 x}

x^{4} e^{- x}

ln (x + 3) - 1

What is the inverse of f(x)=((x+7))/(x-3) ?
The inverse of f(x)=((x+7))/(x-3) is (7+3x)/(x-1)