What is the inverse of f(x)=2(x+3)^2+4 ?

The inverse of f(x)=2(x+3)^2+4 is sqrt((x-4)/2)-3,-sqrt((x-4)/2)-3

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inverse of f(x)=2(x+3)^2+4

inverse

f (x) = 2 (x + 3)^{2} + 4

\frac{x - 4}{2} - 3, - \frac{x - 4}{2} - 3

Solution steps

y = 2 (x + 3)^{2} + 4

Replace

x

with

y

x = 2 (y + 3)^{2} + 4

Solve for

y, x = 2 (y + 3)^{2} + 4

\frac{x - 4}{2} - 3, - \frac{x - 4}{2} - 3

f (x) = x^{3} + 5 x^{2} - 2 x + 10

f (x) = \frac{x ^{3}}{x - 2}

f (x) = 5 csc (\frac{1}{2} π x - \frac{1}{6} π)

f (x) = \frac{x ( x - 2 ) ^{2}}{( x + 5 ) ^{3}}

y = x^{2} - 9

What is the inverse of f(x)=2(x+3)^2+4 ?
The inverse of f(x)=2(x+3)^2+4 is sqrt((x-4)/2)-3,-sqrt((x-4)/2)-3