What is the intercepts of f(x)=2(x+1)(x-3)(x-2)^2 ?

The intercepts of f(x)=2(x+1)(x-3)(x-2)^2 is X Intercepts: (-1,0),(3,0),(2,0),Y Intercepts: (0,-24)

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intercepts of f(x)=2(x+1)(x-3)(x-2)^2

intercepts

f (x) = 2 (x + 1) (x - 3) (x - 2)^{2}

X Intercepts : (- 1, 0), (3, 0), (2, 0), Y Intercepts : (0, - 24)

Solution steps

x -

axis interception points of

2 (x + 1) (x - 3) (x - 2)^{2} : (- 1, 0), (3, 0), (2, 0)

y -

axis interception point of

2 (x + 1) (x - 3) (x - 2)^{2} : (0, - 24)

X Intercepts : (- 1, 0), (3, 0), (2, 0), Y Intercepts : (0, - 24)

x^{2} + 4 x - 6 = 0

\frac{- 10}{x ^{2} + 5}

2 e^{x}

- \frac{2 x}{( x + 1 ) ^{2} ( x - 1 ) ^{2}}

\frac{x}{x ^{2} - 16}

What is the intercepts of f(x)=2(x+1)(x-3)(x-2)^2 ?
The intercepts of f(x)=2(x+1)(x-3)(x-2)^2 is X Intercepts: (-1,0),(3,0),(2,0),Y Intercepts: (0,-24)