What is the inverse of f(x)=(x-13)^2,x<= 13 ?

The inverse of f(x)=(x-13)^2,x<= 13 is sqrt(x)+13,-sqrt(x)+13

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inverse of f(x)=(x-13)^2,x<= 13

inverse

f (x) = (x - 13)^{2}, x \leq 13

x + 13, - x + 13

Solution steps

y = (x - 13)^{2}

Replace

x

with

y

x = (y - 13)^{2}

Solve for

y, x = (y - 13)^{2}

x + 13, - x + 13

y = 3 sin (2 x)

y = x

f (x) = 3 x^{2} - 5 x + 2

f (x) = \frac{3 x ^{2} - 5 x + 2}{2 x ^{2} - 2}

- \frac{2}{3} x

What is the inverse of f(x)=(x-13)^2,x<= 13 ?
The inverse of f(x)=(x-13)^2,x<= 13 is sqrt(x)+13,-sqrt(x)+13