What is the asymptotes of h(x)=(9x^2-16)/(2(3x+4)^2) ?

The asymptotes of h(x)=(9x^2-16)/(2(3x+4)^2) is Vertical: x=-4/3 ,Horizontal: y= 1/2

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asymptotes of h(x)=(9x^2-16)/(2(3x+4)^2)

asymptotes

h (x) = \frac{9 x ^{2} - 16}{2 ( 3 x + 4 ) ^{2}}

Vertical : x = - \frac{4}{3}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{9 x ^{2} - 16}{2 ( 3 x + 4 ) ^{2}} : x = - \frac{4}{3}

Horizontal Asymptotes of

\frac{9 x ^{2} - 16}{2 ( 3 x + 4 ) ^{2}} : y = \frac{1}{2}

Slant Asymptotes of

\frac{9 x ^{2} - 16}{2 ( 3 x + 4 ) ^{2}} :

None

Vertical : x = - \frac{4}{3}, Horizontal : y = \frac{1}{2}

m = \frac{5}{3}, (- \frac{1}{2}, \frac{5}{2})

(20.1) (4.2)

f (x) = e^{2 x}

(4, 3), (2, - 1)

f (x) = - \frac{1}{x ^{2}}

What is the asymptotes of h(x)=(9x^2-16)/(2(3x+4)^2) ?
The asymptotes of h(x)=(9x^2-16)/(2(3x+4)^2) is Vertical: x=-4/3 ,Horizontal: y= 1/2