What is the inverse of f(x)=(6x)/(x^2+49) ?

The inverse of f(x)=(6x)/(x^2+49) is (3+sqrt(-49x^2+9))/x ,(3-sqrt(-49x^2+9))/x

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inverse of f(x)=(6x)/(x^2+49)

inverse

f (x) = \frac{6 x}{x ^{2} + 49}

\frac{3 + - 49 x ^{2} + 9}{x}, \frac{3 - - 49 x ^{2} + 9}{x}

Solution steps

y = \frac{6 x}{x ^{2} + 49}

Replace

x

with

y

x = \frac{6 y}{y ^{2} + 49}

Solve for

y, x = \frac{6 y}{y ^{2} + 49}

\frac{3 + - 49 x ^{2} + 9}{x}, \frac{3 - - 49 x ^{2} + 9}{x}

x = - 5, (1, 4)

f (x) = (x - 4) (x + 1)

f (x) = arcsin (x + 3)

\frac{x cos ( a + x )}{sin ( a + x ) - sin ( a )}

- 2 x^{2} + 2 x

What is the inverse of f(x)=(6x)/(x^2+49) ?
The inverse of f(x)=(6x)/(x^2+49) is (3+sqrt(-49x^2+9))/x ,(3-sqrt(-49x^2+9))/x