What is the range of f(x)=(3x-1)/(x+2) ?

The range of f(x)=(3x-1)/(x+2) is f(x) 3

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range of f(x)=(3x-1)/(x+2)

range

f (x) = \frac{3 x - 1}{x + 2}

f (x) < 3 or f (x) > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{3 x - 1}{x + 2}

Inverse of

\frac{3 x - 1}{x + 2} : \frac{- 1 - 2 x}{x - 3}

\frac{- 1 - 2 x}{x - 3}

Find the domain of each inverse function

Domain of

\frac{- 1 - 2 x}{x - 3} : x < 3 or x > 3

Combine the intervals

f (x) < 3 or f (x) > 3

x^{2} + 2 x - 15

R (x) = \frac{x ^{2} - x - 12}{x + 6}

x^{4} - 4 x^{2}

f (x) = 8^{x} - 9

f (x) = 2 x^{3} + 3 x - 2 g (- 7) = - 1

What is the range of f(x)=(3x-1)/(x+2) ?
The range of f(x)=(3x-1)/(x+2) is f(x)<3\lor f(x)>3