What is the perpendicular y= 3/2 x,(2,3) ?

The perpendicular y= 3/2 x,(2,3) is y=-2/3 x+13/3

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perpendicular y= 3/2 x,(2,3)

perpendicular

y = \frac{3}{2} x, (2, 3)

y = - \frac{2}{3} x + \frac{13}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{2} x

that passes through

(2, 3)

Find the slope of

y = \frac{3}{2} x : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(2, 3) : y = - \frac{2}{3} x + \frac{13}{3}

y = - \frac{2}{3} x + \frac{13}{3}

- x^{2} - 36 + 6

f (x) = lo g_{2} (4 - x^{4})

f (x) = \frac{x + 3}{x - 2}

f (x) = \frac{( x - 8 )}{( x - 3 ) ( x + 5 )}

\frac{x}{5 + x ^{2}}

What is the perpendicular y= 3/2 x,(2,3) ?
The perpendicular y= 3/2 x,(2,3) is y=-2/3 x+13/3