What is the asymptotes of f(x)=((x^2-3x))/((x^2-9)) ?

The asymptotes of f(x)=((x^2-3x))/((x^2-9)) is Vertical: x=-3,Horizontal: y=1

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asymptotes of f(x)=((x^2-3x))/((x^2-9))

asymptotes

f (x) = \frac{( x ^{2} - 3 x )}{( x ^{2} - 9 )}

Vertical : x = - 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 9} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 9} :

None

Vertical : x = - 3, Horizontal : y = 1

f (x) = 1 - 2 lo g_{5} (x)

f (x) = - x + 1

f (x) = x^{2} - x - 2

\frac{4 x - 9}{5 x + 3}

27 - x^{3}

What is the asymptotes of f(x)=((x^2-3x))/((x^2-9)) ?
The asymptotes of f(x)=((x^2-3x))/((x^2-9)) is Vertical: x=-3,Horizontal: y=1