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Popular >

midpoint (-4,5),(7,-9)

Solution

midpoint

(- 4, 5), (7, - 9)

Solution

(\frac{3}{2}, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 4, 5), (x_{2}, y_{2}) = (7, - 9)

= (\frac{7 - 4}{2}, \frac{- 9 + 5}{2})

Refine

= (\frac{3}{2}, - 2)

Popular Examples

extreme X^2+1 extreme points

X^{2} + 1

distance (0,10),(5,-1)distance

(0, 10), (5, - 1)

extreme f(x)=6e^{2x}x-7e^{2x}extreme points

f (x) = 6 e^{2 x} x - 7 e^{2 x}

critical x/(x^2+6x+5)critical points

\frac{x}{x ^{2} + 6 x + 5}

inverse of 3/2 x^4 inverse

\frac{3}{2} x^{4}

Frequently Asked Questions (FAQ)

What is the midpoint (-4,5),(7,-9) ?
The midpoint (-4,5),(7,-9) is (3/2 ,-2)