What is the global f(x)=-x^2+11 ?

The global f(x)=-x^2+11 is Global Maximum(0,11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

global f(x)=-x^2+11

global extreme points

f (x) = - x^{2} + 11

Global Maximum (0, 11)

Solution steps

Find the extreme points:

Maximum

(0, 11)

Find the function range:

(- \infty, 11]

Verify extreme points are global points

Global Maximum (0, 11)

f (x) = (x - 8)^{7}

f (x) = (4 - 3 x)^{2}

f (x) = 5 x^{3} - 3 x

g (t) = \frac{3}{t}

y = - \frac{x}{2} - 6, (- 8, 1)

What is the global f(x)=-x^2+11 ?
The global f(x)=-x^2+11 is Global Maximum(0,11)