What is the perpendicular 8x+6y=-60 ?

The perpendicular 8x+6y=-60 is y= 3/4 x+b

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perpendicular 8x+6y=-60

perpendicular

8 x + 6 y = - 60

y = \frac{3}{4} x + b

Solution steps

Find the slope of

8 x + 6 y = - 60 : m = - \frac{4}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{4}

Line with slope m=

\frac{3}{4} : y = \frac{3}{4} x + b

y = \frac{3}{4} x + b

f (x) = x^{2} + 4 x + 4

f (x) = x + 5 + 1

(x - 2) (x - 6)^{3} + 6

f (x) = x^{4} - 4 x^{3} + 8

f (x) = \frac{1}{2} (x - 1)^{2} + 3