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Popular >

range of x^2+6x+5

Solution

range

x^{2} + 6 x + 5

Solution

f (x) \geq - 4

+1

Interval Notation

[- 4, \infty)

Solution steps

Vertex of

x^{2} + 6 x + 5 :

Minimum

(- 3, - 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (- 3, - 4)

f (x) \geq - 4

Popular Examples

domain of f(x)=sqrt(4x-9)domain

f (x) = 4 x - 9

inverse of f(x)=log_{8}(x)inverse

f (x) = lo g_{8} (x)

inverse of y=3+3x inverse

y = 3 + 3 x

critical f(x)=-2/(x^2)critical points

f (x) = - \frac{2}{x ^{2}}

critical f(x)=x^4-3x^2+6 critical points

f (x) = x^{4} - 3 x^{2} + 6

Frequently Asked Questions (FAQ)

What is the range of x^2+6x+5 ?
The range of x^2+6x+5 is f(x)>=-4