What is the slope ofintercept-8x+y-8=0,(2,5) ?

The slope ofintercept-8x+y-8=0,(2,5) is y=8x+8

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slope ofintercept-8x+y-8=0,(2,5)

slope intercept

- 8 x + y - 8 = 0, (2, 5)

y = 8 x + 8

Solution steps

- 8 x + y - 8 = 0

Convert to slope intercept form:

y = 8 x + 8

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = 8 x + 8

f (x) = 1 - 2 e^{- 2 x}

2 x^{2} - 12 x + 20

f (x) = 2 x^{2} + x - 4

f (x) = 3 + \frac{x ^{2} - 10}{x - 2}

y = x^{2} + 2 x + 18

What is the slope ofintercept-8x+y-8=0,(2,5) ?
The slope ofintercept-8x+y-8=0,(2,5) is y=8x+8