What is the domain of f(x)=sqrt(x^2-6x+8) ?

The domain of f(x)=sqrt(x^2-6x+8) is x = 4

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domain of f(x)=sqrt(x^2-6x+8)

domain

f (x) = x^{2} - 6 x + 8

x \leq 2 or x \geq 4

Interval Notation

(- \infty, 2] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 4

The function domain

x \leq 2 or x \geq 4

\frac{2 x}{x ^{2} + 2 x}

(4, 0), (20, 18)

(3 - x) e^{- x}

y = \frac{1}{x}

f (x) = 4 x^{3} + 5

What is the domain of f(x)=sqrt(x^2-6x+8) ?
The domain of f(x)=sqrt(x^2-6x+8) is x<= 2\lor x>= 4