What is the domain of f(x)=(x+3)/(3x-27)+1/(x^2-4) ?

The domain of f(x)=(x+3)/(3x-27)+1/(x^2-4) is x 9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+3)/(3x-27)+1/(x^2-4)

domain

f (x) = \frac{x + 3}{3 x - 27} + \frac{1}{x ^{2} - 4}

x < - 2 or - 2 < x < 2 or 2 < x < 9 or x > 9

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or 2 < x < 9 or x > 9

\frac{10 - x}{x ^{2} - 1}

f (x) = - 2 x - 10

y = - 3 + 5

sin (3 x)

f (x) = 1 + 2 x^{5}

What is the domain of f(x)=(x+3)/(3x-27)+1/(x^2-4) ?
The domain of f(x)=(x+3)/(3x-27)+1/(x^2-4) is x<-2\lor-2<x<2\lor 2<x<9\lor x>9