What is the extreme f(x)=2x^3+3x^2-1 ?

The extreme f(x)=2x^3+3x^2-1 is Maximum(-1,0),Minimum(0,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3+3x^2-1

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 1

Maximum (- 1, 0), Minimum (0, - 1)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 1

into

2 x^{3} + 3 x^{2} - 1 : 0

Maximum (- 1, 0)

Plug

x = 0

into

2 x^{3} + 3 x^{2} - 1 : - 1

Minimum (0, - 1)

Maximum (- 1, 0), Minimum (0, - 1)

f (x) = \frac{1}{[ x + 3 ]}

f (x) = - x^{4} - 3 x^{3} + 8 x + 8

y = ln (x) + 7

f (x) = 2.5 sin (2 x)

f (x) = ln (x) - ln (x + 1)

What is the extreme f(x)=2x^3+3x^2-1 ?
The extreme f(x)=2x^3+3x^2-1 is Maximum(-1,0),Minimum(0,-1)