What is the inverse of f(x)=(8x+9)/(1-4x) ?

The inverse of f(x)=(8x+9)/(1-4x) is -(9-x)/(4(2+x))

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inverse of f(x)=(8x+9)/(1-4x)

inverse

f (x) = \frac{8 x + 9}{1 - 4 x}

- \frac{9 - x}{4 ( 2 + x )}

Solution steps

y = \frac{8 x + 9}{1 - 4 x}

Replace

x

with

y

x = \frac{8 y + 9}{1 - 4 y}

Solve for

y, x = \frac{8 y + 9}{1 - 4 y}

- \frac{9 - x}{4 ( 2 + x )}

f (x) = 3 x - 5

f (x) = - 3 x + 5

\frac{1}{x + 3}

- x + 7

y = ln (x^{3} sin^{2} (x))

What is the inverse of f(x)=(8x+9)/(1-4x) ?
The inverse of f(x)=(8x+9)/(1-4x) is -(9-x)/(4(2+x))