What is the domain of f(x)=-7/(2t^{(3/2))} ?

The domain of f(x)=-7/(2t^{(3/2))} is t>0

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domain of f(x)=-7/(2t^{(3/2))}

domain

f (x) = - \frac{7}{2 t ^{(\frac{3}{2})}}

t > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 0

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t > 0

\frac{x ^{2} + 1}{x ^{2} - x - 2}

f (x) = x^{2} - 5 x - 24

f (x) = 2 x^{3} + x^{2} - 8 x + 3

x e^{\frac{2}{x}} + 1

\frac{2 x ^{2} + 7 x - 30}{2 x - 5}

What is the domain of f(x)=-7/(2t^{(3/2))} ?
The domain of f(x)=-7/(2t^{(3/2))} is t>0